Question

two dice are thrown at the same time find the probability of getting a multiple of 3 on first die and multiple of
2nd die​

Answer 1

ans is 1/6 think you ca further solve

Answer 2

2 dice are thrown at the same time so

S= { (1, 1) (2, 2) (3,3) (4,4) (5,5) (6,6) (1,6) (1,5) (1,4) (1,3) (1,2) (2,1), (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,4) (3,5) (3,6) (4,1) (4,2),(4,3) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5)}

n(S) =36

let A be the event that the number on the first die is a multiple of 3

A= {(3,1) (3,3), (3,4) (3,5) (3,6) (3,2) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6) }

n(A)= 12

p(A) = n(A) / n(S)

=12 / 36

= 1/3

The probability of getting a multiple of 3 on the first die is 1/3



Let the B be the event of getting a multiple of 2 on the second die
B={ (1, 2) (1, 4) (1, 6) (2, 2) (2, 4) (2, 6) (3, 2) (3, 4) (3, 6) (4, 2) (4, 4) (4, 6) (5, 2) (5, 4) (5, 6) (6,2) (6, 4) (6, 6)

n(B) = 18

p(B)= n(B) /n(S)
= 18/36
=1/3
The probability of getting a multiple of 2 on the second die is also 1/3

that's about it. I hope it helps