Math, asked by sruthisajesh1635, 11 months ago

Two dice are thrown at the same time.find the probability of getting
A) both are same face
B) sum of two numbers appearing an two dice is greater than 9

Answers

Answered by chordiasahil24
5

Answer:

(A) 1/6

(B) 1/2

Step-by-step explanation:

n(s)=36

E1= both are same face (which means the number appeared should be same on both dices)

n(E1)=6

P(E1)=6/36

=1/6

E2= sum of two numbers appearing an two dice is greater than 9

n(E2)=18

P(E2)=18/36

=1/2

HOPE IT HELPS U


Meghana625625: Your second solution is wrong
theironman: hii
chordiasahil24: Yeah
chordiasahil24: My bad
theironman: hii
Answered by shadowsabers03
8

As there are two dice, the total no. of outcomes is 6^2 = 36.

(A) There are a total of 6 possibilities in which the numbers in both the dice are same: (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6).So the probability is 6/36 = 1/6

(B) The possibilities in which the sum of the numbers in the dice is greater than 9 are given: (4, 6), (5, 5), (5, 6), (6, 4), (6, 5), (6, 6). Thus the no. of favourable outcomes is 6. So the probability is also 6/36 = 1/6.

Thank you...

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