Question

Two dice are thrown. Find the odd in favour of getting the sum 5 and the odds against getting the sum​

Answer 1

(5) = {4}

other sums = {32}

Answer 2

Answer

Odds in favour = 1/9 = 11.1%

Odds against = 8/9 = 88.8%

Step-by-step explanation:

Possible outcomes of getting sum 5 when two die (plural for 2 dice) are thrown:  1+4, 2+3, 3+2, 4+1

Therefore, possible outcomes = 4

Total outcomes are 36 (1+1, 1+2, 1+3,.....2+1,2+2,2+3........till 6+6)

P (getting sum 5)  = P.O/T.O

                             = 4/36

                             =   1/9

                             =   11.1% (chance of happening)

Therefore, possible outcomes of not getting sum 5 = 32, (possible outcomes are 4, therefore not possible outcomes = 36 - 4= 32)

P (not getting sum 5) = P.O/T.O

                                   =  32/36

                                   =   8/9

                                   =   88.8% (chance of not happening)

Hope this helps!!

Cheers!!