two dice are thrown. Find the probability of getting.
(a) Same number on both the dice (b) Sum of the numbers appeared 11 (c) Sum 13
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Answer:
n (S) =12
a) let A be the probability of getting same no. on both sides
n (A)=6
=) P (A)=n (A)/n (S)
=) P (A)=6/12 =1/2
b) let B be the probability for the sum as 11.
B={(6,5) , (5,6)}
n (B)=2
=) P (B) = n(B)/n (S)
=) P (B) =2/11
c) let C be the probability of getting sum 13
not possible
so, P (C)=0
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