two dice are thrown. find the probability of getting an odd number on one die and a multiple of 3 on the other.
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Answered by
3
Probability of getting an odd number is 3/6=1/2 (1,3,5)
Probability of getting a multiple of 3 4/6=2/3(1,2,3,6 itself )
Probability of getting a multiple of 3 4/6=2/3(1,2,3,6 itself )
suriyaprakash3:
thanks a lot!!!!!
Answered by
4
Hey dear...
Your answer is. ..
We know in a dice there are 6 numbers .
3 (1,3,5) are odd and 3 (2,4,6) are even .
So the probability of getting odd number is
3/6
The multiple of 3 are 1,3,6
So the probability is 3 /6 .
Hope this helps. Thank you.
Your answer is. ..
We know in a dice there are 6 numbers .
3 (1,3,5) are odd and 3 (2,4,6) are even .
So the probability of getting odd number is
3/6
The multiple of 3 are 1,3,6
So the probability is 3 /6 .
Hope this helps. Thank you.
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