Question

Two dice are thrown find the probability of getting sum as a cube and divisible by 3

Answer 1

Total no of outcomes, here are = 36

No of possible outcomes are = 0, as there are no cubes here which can be divisible by 3.

Therefore,

P(E) = 0/36 = 0

If you don't know the total no of outcomes, you can see them below:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)