two dice are thrown. find the probability of getting sum of 10
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There are a total of 36 combinations in throw of 2 dice.
The sum of 10 could be obtained in the following cases:
5+5,4+6,6+4
That is a total of 3 cases. Therefore the required probability here is:
3/36= 1/12
Please mark me as brianliest
The sum of 10 could be obtained in the following cases:
5+5,4+6,6+4
That is a total of 3 cases. Therefore the required probability here is:
3/36= 1/12
Please mark me as brianliest
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