two dice are thrown find the probability of getting the sum of two number on the die greater than 6 but less than 9
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Answered by
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I f two dice are thrown then the total number of outcomes is equal to 36.
And favorable outcomes are--
3+4,4+3,4+4
So,
P (E)=No. of favourable outcomes /Total no. of outcomes.
=3/36
=1/12
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And favorable outcomes are--
3+4,4+3,4+4
So,
P (E)=No. of favourable outcomes /Total no. of outcomes.
=3/36
=1/12
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Please marked as branlist.
pradeep8358:
as given in book
The no. on first die is 3 then 2 will be 4
ok wait
okk
my ans is 11/36 see. y steps
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Answered by
7
Let E be the event 'the sum of two nymber on the die greater than 6 but less than 9'
Total possibilities = 11
Total probability = 36
Therefore, probability of E = 11/36
Total possibilities = 11
Total probability = 36
Therefore, probability of E = 11/36
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