Question

Two Dice are thrown. Find the probability of the events
i)The product of numbers on their upper faces is 12
ii) The sum of the numbers on their upper faces is multiple of 7​

Answer 1

Answer:

hope it's helpful sweetie

Step-by-step explanation:

Let E be the favorable event, then

E={(2,6),(6,2),(4,3),(3,4)}

So n(E)=4

Also sample space n(S)=6×6=36

Hence required probability is =

n(S)/n(E)= 36/4

= 9/1