Question

two dice are thrown in the air, the probability of getting sum as 3 will

be

(a) 1/36 (b) 5/36 (c) 2/36 (d) 3/36​

Answer 1

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$\huge\bf{Answer:-}$

Given:-

• two dice are thrown in air,

To find:

• probability of getting sum as 3

Solution:-

Each dice has 6 possible outcomes from 1 to 6

Hence possible outcomes for 2 dice are

• = 6 × 6
• = 36
• n(S) = 36
• Event E is sum of both dice = 3

• E = { ( 1, 2) , ( 2, 1)}

• n(E) = 2

• P(E) = n(E)/n(S)

• => P(E) = 2/36

• => P(E) = 1/1

probability of getting sum as 3 = 1/18

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