Question

Two dice are thrown once. the probability of getting a sum of 8 is

a) 0
b) 1/36
c) 5/36
d) 7/36​

Answer 1

Answer:

5/36

Step-by-step explanation:

The possible outcomes when two dice are thrown together are:

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6).

Therefore, the number of possible outcomes when two dice are thrown is 36.

Now, the possible outcomes of getting a sum equal to 8 is {(2,6),(3,5),(4,4),(5,3),(6,2)}, which means the number of favourable outcome is 5.

Therefore, probability P of getting a sum equal to 8 is:

P=

36

5

Hence, the probability of getting a sum equal to 8 is

36

5

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.

Answer 2

Answer:

C) 5/36

Step-by-step explanation:

First die there are 6 possible outcomes for the second

Therefore

Possible outcomes ⇒ 6 × 6 = 36

Sum should p + q = 8 :-