Question

two dice are thrown simultaneously 500 times each time the sum of two numbers appearing on their tops is noted and recorded as given in the following table
if the dice are thrown once more what is the probability of getting sum a)3
b)more then 10
c)less then or equal to 5
d)between 8 & 12

Answer 1

If the dice are rolled once more than the no. of possible events are 6*6=36
1.no. of favorable events=(1, 2),(2,1)=2
Probability of getting sum of 3 is=2/36=1/18

2.no. of favorable events=(6, 5),(5,6),(6,6)=3
Probability of getting a sum of more than 10=3/36=1/12

3. No. of favorable events=(1,1),(1,2),(2,1),(1,3),(3,1),(2,2),(4,1),(1,4),(2,3),(3,2)=10


4.no. Of favorable events =9
Probability of getting a sum between 8 and 12=9/36=1/4