Math, asked by kulkarnishreyas2806, 4 months ago

Two dice are thrown simultaneously 500 times. Each time the sum of
two numbers appearing on them is noted and recorded in the following table:
Sum
2 3 4 5 6 7 8 9 10 11
Frequency 14 30 42 55 72 75 70
53
46 28
From the above data, what is the probability of getting a sum:
(i) more than 10
(ii) between 8 and 12.
15

Answers

Answered by Anonymous
0

Sum            2  3    4    5  6    7   8   9   10  11  12

Frequency 14 30 42 55 72 75 70 53 46 28 15  

Total outcomes=500

i)P[of getting a sum 3]=30/500

                                   =3/50

                                   =0.06

ii)P[of sum more than 10]=89/500

                                        =17.8/100

                                        =0.178                  

iii)P[sum less than or equal to 5]=141/500

                                                    =28.2/100

                                                    =0.282

iv)P[sum between 8 and 12]=127/500

                                             =25.4/100

                                             =0.254  

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