Math, asked by dakchakchmarak, 3 months ago

Two dice are thrown simultaneously 500 times. Each time the sum of two numbers appearing on their tops is noted and recorded as given in the following table: Sum Frequency 2 14 3 30 4 42 5 55 6 72 If the dice are thrown once more, what is the probability of getting a sum less than or equal to 5?

Answers

Answered by freefire1237

Answer:

5/6

Step-by-step explanation:

mark me branliest if you like my answer

Answered by nehaliganvit3

Step-by-step explanation:

If we rolled dice around 500 times then it can be considered as its expected outcome, hence the probability of obtaining more than 10 as sum (28+15)/500=0.086

Previous Question

Next Question

Two dice are thrown simultaneously 500 times. Each time the sum of two numbers appearing on their tops is noted and recorded as given in the following table: Sum Frequency 2 14 3 30 4 42 5 55 6 72 If the dice are thrown once more, what is the probability of getting a sum less than or equal to 5?​

Answers

Two dice are thrown simultaneously 500 times. Each time the sum of two numbers appearing on their tops is noted and recorded as given in the following table: Sum Frequency 2 14 3 30 4 42 5 55 6 72 If the dice are thrown once more, what is the probability of getting a sum less than or equal to 5?