Question

Two dice are thrown simultaneously.

a. Find the probability of getting a doublet.

b. Find the probability that the difference between two numbers on the dice will be 5.

c.Find the probability that the sum of numbers on the two dice would be 7 or more.


NOTE : If you whish please give me relevant answers and don't type nonsense​

Answer 1

Answer:

refer the above attachment

DROP SOME THANKS

Answer 2

Ans.a

Two dice are throw. So Total number of possible outcomes are 36.

Number of favourable cases = 6

$\textbf{Required Probability = } \frac{6}{36} = \frac{1}{6}$

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Ans.b

Given:- Two dice one throw simultaneously.

To Find:- Probability to come 5 on both side.

Solve:-

Total Number of outcome = 36

Total Favourable outcome = 1

Hence,

$\text{Probability = } \frac{\sf \colorbox{god} {No. of Favourable outcome }}{\sf \colorbox{god} {Total No. of outcome}}$

$= \textbf{Answer is } \frac{1}{36}$

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Ans.c

• look at the pic!

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