Question

Two dice are thrown simultaneously. a) Find the probability of getting a doublet. b) find the probability of getting the sum of numbers as 8. c) Find the probability of getting that the difference between two numbers on the dice will be​

Answer 1

Answer:

a) probability of getting a doublet is 1/6

b) probability of getting sum as 8 is 5/36

Step-by-step explanation:

sample space of the event is,

(S)= {(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}

n(S) = 36

a) let the event of getting a doublet be E

n(E) = 6

P(E)= $\frac{number of outcomes}{total number of outcomes}$

P(E)= 6/36

P(E)= 1/6

b) let the event of getting sum as 8 be F

n(F)=5

P(F)= 5/36