Question

two dice are thrown simultaneously. determine the probability that the difference of the numbers on the dice is 2

Answer 1

there are 8 possibilities out of 36
possibility is 4÷18

Answer 2

The probability that the difference of the numbers on the dice is 2 is $\dfrac{1}{6}$.

Step-by-step explanation:

Given : Two dice are thrown simultaneously.

To find : The probability that the difference of the numbers on the dice is 2?

Solution :  

When two dice are thrown,

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)  

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)  

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)  

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)  

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)  

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)  

The favorable outcome that the difference of the numbers on the dice is 2 i.e. {(1,3),(3,1),(4,6),(6,4),(5,3),(3,5)}= 6

Total number of outcome = 36

The probability that the difference of the numbers on the dice is 2 is given by,

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total outcome}}$

$\text{Probability}=\frac{6}{36}$

$\text{Probability}=\frac{1}{6}$

#Learn more  

If two dice are thrown simultaneously, then the probability of getting a doublet or a total of 6 is

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