Question

Two dice are thrown simultaneously find : odds against getting a sum of numbers 6​

Answer 1

Answer:

⇒n(E1)=5. Thus, E1 occurs in 5 ways and does not occur in (36 - 5) = 31 ways. ∴ odds in favour of getting the sum 6=5:31.

Answer 2

5/36

5/6 × 1/6 = 5/36. So the odds that you'll roll 2 dice totalling six are 5/36 each time you roll ( or approximately 1 chance in 7).