Two dice are thrown simultaneously find prob tgat sum if two number on top is less than or equal to 10
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The probable outcomes for sum greater than 10 are (6,6),(6,5),(5,6) = 3
Total no. of probable outcomes = 36
So, the probable no. of outcomes for the sum less than or equal to 10 = 36-3=33
Hence required probability = 33/36 = 11/12
Total no. of probable outcomes = 36
So, the probable no. of outcomes for the sum less than or equal to 10 = 36-3=33
Hence required probability = 33/36 = 11/12
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