Question

two dice are thrown simultaneously find probability of getting a sum more than 8​

Answer 1

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▪︎ Two dice are thrown simultaneously.

▪︎ Therefore outcomes whose sum is more that 8 = (3,6), (4,5), (4,6), (5,4), (5,5), (5,6), (6,3), (6,4), (6,5), (6,6).

▪︎ So number of outcomes whose sum is more than 8 = 10.

▪︎ And total number of outcomes = 6 × 6 = 36.

$\implies$ p(of getting sum more than 8)

= No of fav. outcome/Total no. of outcomes

$=\frac{10}{36} \\ \\ =\frac{5}{18}$

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Answer 2

Answer: hello...

Two dice are thrown simultaneously.

▪︎ Therefore outcomes whose sum is more that 8 = (3,6), (4,5), (4,6), (5,4), (5,5), (5,6), (6,3), (6,4), (6,5), (6,6).

▪︎ So number of outcomes whose sum is more than 8 = 10.

▪︎ And total number of outcomes = 6 × 6 = 36.

p(of getting sum more than 8)

= No of fav. outcome/Total no. of outcomes

10 /36

= 5/18 ...is the probability....

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