Question

Two dice are thrown simultaneously. Find the probability of : 1. getting a sum ≤ 3

Answer 1

Answer:

Total no. of possible outcomes = 36

(1,1) , (1, 2) and (2, 1) are different outcomes.

Therefore, probability of getting ‘sum ≤ 3’

= 3/36

  = 1/12

Hope it helps!

happy learning

Answer 2

Answer:

hey mate

here is the answer

➡️total outcomes = 12 ( 1,2,3,4,5,6,1,2,3,4,5,6)

➡️possible outcomes = 3 {(1,1) , (1,2) , (2,1) }

➡️therefore probability (getting a sum ≤ 3)=

➡️favourable outcomes / total outcomes

➡️=3/12

➡️=1/4

hope it helps you deaR..❗️

✌✌

☆ plz like and mark brainliest