Question

Two dice are thrown simultaneously. Find the probability of: 1. getting a sum of at least 11

Answer 1

Answer:

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The total number of possibilities is 6 for the first die and 6 for the second. Since each throw on the first die could be paired with any of the six on the second, the total ways the dice could fall is 6 × 6 = 36. So the probability of getting 11 or more is 3/36 = 1/12.

Answer 2

Answer:

The total number of possibilities is 6 for the first die and 6 for the second.

Since each throw on the first die could be paired with any of the six on the second, the total ways the dice could fall is 6 × 6 = 36.

So the probability of getting 11 or more is 3/36 = 1/12.