two Dice are thrown simultaneously.find the probability of getting an even number as the sum
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favourable outcomes=(1, 1), (1, 3), (1, 5), (2, 2), (2, 4), (2, 6), (3, 1) (3, 3), (3, 5), (4, 2), (4, 4), (4, 6), (5, 1), (5, 3), (5, 5), (6, 2), (6, 4), (6, 6)
So probability= no. of favourable outcomes/total no of outcomes= 18/36=1/2
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