Question

Two dice are thrown simultaneously. Find the probability of getting a doublet.

Answer 1

total outcomes of two dice is 36
favourable event is 6
probability = favorable event ÷ total outcome
=6÷36
=1÷6 is the answer

Answer 2

Total outcomes = 36

Possible outcomes = (1,1), (2,2), (3,3), (4,4), (5,5) and (6,6)

Total number of possible outcomes = 6

$P(doublets) = \frac{6}{36} \\ = \frac{1}{6}$