Question

Two dice are thrown simultaneously find the probability of getting a multiple of 5 as the sum

Answer 1

Answer:

7/36

Step-by-step explanation:

probability=

favorable outcomes/total outcome

• total outcomes of the two dice when thrown simultaneously:-

1. (1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
2. (2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
3. (3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
4. (4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
5. (5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
6. (6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

*total 36 pairs in all.

• favorable outcomes which are multiple of 5 as sum:-

(1,4),(2,3),(3,2),(4,1),(4,6)(5,5),(6,4)

*total 7 pairs.

probability=7/36

probability= 7

Answer 2

Answer:

7/36

Explanation:

Favourable cases:-

(1,4) (2,3) (3,2) (4,1) (4,6) (5,5) (6,4) –7

Total number of cases:-

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6) –36

P=7/36

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