two dice are thrown simultaneously find the probability of getting a sum less than 9
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Step-by-step explanation:
1 2 3 4 5 6
1 (1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
2 (2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
3 (3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
4 (4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
5 (5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
6 (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
n(S)=6squre=36
no. of getting sum less than 9,n(letA)=26
probality getting A ,p(A)=n(A)/n(S)
= 26/36
=13/18ans
aishwarya18004:
thank you
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