Question

Two dice are thrown simultaneously find the probability of getting that sum of two no is 10

Answer 1

Step-by-step explanation:

SAMPLE SPACE OF TWO DICE IS :

(1,1), (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1), (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1), (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1), (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1), (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1), (6,2) (6,3) (6,4) (6,5) (6,6)

THEREFORE, TOTAL CASES : 36

SUM AS 10: (6,4)(4,6)(5,5)

NO. OF FAVORABLE OUTCOMS : 3

PROBABILITY OF EVENT = NO. OF FAVOUARABLE OUTCOMES /TOTAL NO. OF OUTCOMS

= 3/36 =1/12

!!HOPE IT HELPS !!