Question

Two dice are thrown simultaneously. Find the probability of getting:
(1) an even number as the sum
(2) a total of at least 10;
(3) same number on both dice i.e. a doublet
(4) a multiple of 3 as the sum.

Answer 1

Answer:

Step-by-step explanation:

Total no. of outcomes=36

P(even number as sum)=18361836

P(sum as prime number)=15361536

P( a total of atleast 10)=636636

P(doublet of even number)=936936

P(a multiple of 2 on one dice and 3 on other)=936936

P(same no. on both dice)=636636

P( a multiple of 3 as sum)=1236