two dice are thrown simultaneously. find the probability of getting a doublet of even number
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The event is getting a doublet i.e. getting same number on both the dice and the outcomes (1,1) (2,2) (3,3) (4,4) (5,5) (6,6) are favourable to the event.
So,the number of favourable outcomes=6
=6/36=1/6
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Answer:no.of exhaustive case=36
1,1 1,3 1,5 2,2 2,4 ,2,6 3,1 3,3 3,5 ,4,2 4,4 , 4,6 5,1 5,3 5,5 6,2 6,4 and 6,6
No. Favorable case = 18
Then ,18 /36
Step-by-step explanation:
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