Question

two dice are thrown simultaneously find the probability of getting.
1 )even number as sum.
2) sum as prime numbers.
3) total of atleast 10​

Answer 1

(2) favorable outcomes for sum as prime are (1,1) ,(1,2) , (1,4) , (1,6) , (2,3) , (2,3) , (2,3) , (2,5) , (3,2)

number of favorable outcomes = 15

hence, the probability of getting the sumes a prime number =15/36 =5/12

Answer 2

Step-by-step explanation:

1)even no. as sum

=(1,1),(1,3),(1,5),(2,2)(2,4),(2,6),(3,1),(3,3),(3,5)

(4,2),(4,4),(4,6)(5,1),(5,3),(5,5),(6,2),(6,4),(6,6)

2)sum as prime no.

=((1,1),(1,2),(1,4),(1,6),(2,1),(2,3,(2,5),(3,2),(3,4)

(4,1),(4,3),(5,2),(5,6),(6,1),(6,5)

3)total of at least 10

=(4,6),(5,5),(6,4)

Hope it is helpful

THANKS