Two dice are thrown simultaneously. Find the probability of getting :
i)an even number as the sum
ii)in the sum as a prime number
iii)a total at least 10
iv) a doublet of even number
v)a multiple of 2 on one dice and a multiple of 3 on the other
vi)Same number on both dice ie, a doublet
vii) a multiple of 3 as the sum.
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Above shown is the outcome table when two dice are thrown
[1]sample space when. sum is even
(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)
(1,3),(1,5),(3,1),(5,1),(4,2),(6,2)
(5,3),(2,4),(6,4),(3,5),(2,6),(4,6)
total possibilities=18
total no.of outcoems =36
therefore
probality that sum is even number=18/36
=1/2
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