two dice are thrown simultaneously find the probability of getting a sum 9 is a single throw
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let S be the sample space of the random experiment
n(S) = 6^2 = 36
let A = event of getting a sum of 9 in a single throw
A = { (3,6),(4,5),(5,4),(6,3)}
n(A) = 4
probability P(A)
= n(A)/n(S)
= 4/36
= 1/9
n(S) = 6^2 = 36
let A = event of getting a sum of 9 in a single throw
A = { (3,6),(4,5),(5,4),(6,3)}
n(A) = 4
probability P(A)
= n(A)/n(S)
= 4/36
= 1/9
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