two dice are thrown simultaneously find the probability of at least one of the two throws comes up with the number 4
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Hey Friend,
Number of die = 2
Therefore, number of possible outcomes = 6 x 6 = 36
At least one face should have 4...
Number of favourable outcomes = 3
[4 on first dice OR 4 on second dice OR 4 on both the dies]
Probability (of an event) = Number of favourable outcomes
-------------------------------------------
Number of possible outcomes
P (E) = 3 / 36
= 1 / 12
Therefore, the probability of getting 4 on the face when two die are thrown is 1/12.
Hope it helps!
Number of die = 2
Therefore, number of possible outcomes = 6 x 6 = 36
At least one face should have 4...
Number of favourable outcomes = 3
[4 on first dice OR 4 on second dice OR 4 on both the dies]
Probability (of an event) = Number of favourable outcomes
-------------------------------------------
Number of possible outcomes
P (E) = 3 / 36
= 1 / 12
Therefore, the probability of getting 4 on the face when two die are thrown is 1/12.
Hope it helps!
angel148:
hii
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