Question

two dice are thrown simultaneously.find the probability of getting an even number as the sum

Answer 1

In two die we have 36 outcomes like
1 1. 21 31 41
And in two dies we have 18 even outcome and 18 odd no outcome in die so that the even no in die probability is
1/2

Answer 2

Answer:

$\frac{1}{2}$

Step-by-step explanation:

Given :Two dice are thrown simultaneously

To Find : find the probability of getting an even number as the sum

Solution:

Possible outcomes :

{1,1};{1,2};{1,3};{1,4};{1,5};{1,6}

{2,1};{2,2};{2,3};{2,4};{2,5};{2,6}

{3,1};{3,2};{3,3};{3,4};{3,5};{3,6}

{4,1};{4,2};{4,3};{4,4};{4,5};{4,6}

{5,1};{5,2};{5,3};{5,4};{5,5};{5,6}

{6,1};{6,2};{6,3};{6,4};{6,5};{6,6}

Total outcomes = 36

Favorable events : an even number as the sum :{1,1};{1,3};{1,5};{2,2};{2,4};{2,6};{3,1};{3,3};{3,5};{4,2};{4,4};{4,6};{5,1};{5,3}{5,5};{6,2};{6,4};{6,6} =18

So, the probability of getting an even number as the sum:

= $\frac{\text{Favorable events}}{\text{Total events}}$

= $\frac{18}{36}$

= $\frac{6}{12}$

= $\frac{1}{2}$

Hence the probability of getting an even number as the sum is $\frac{1}{2}$