Two dice are thrown simultaneously find the probability of getting 5 on first die
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Answered by
2
Answer:
1/6 is your answer
Step-by-step explanation:
n(S) = 36
event= getting 5 on first die
= {(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)}
P(event) = n(event) ÷ n(S)
= 6/36
= 1/6
Hope it helped you :)
Answered by
0
Total 6 chance are there where 5 comes on First Dice
So probability = 6/36=1/6
So probability = 6/36=1/6
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