Question

Two dice are thrown simultaneously.find the probability of getting sum of numbers appearing on both sides is less than 12

Answer 1

36 possible outcomes 

P(11, that is either [5,6] or [6,5]) = 2/36. 
P(12, that is [6,6]) = 1/12 
hence P(11 or 12) = P(sum>= 11) = 3/36 = 1/12 

P(sum<11) = 1 - P(sum>=11) = 1 - 1/12 = 11/12

Answer 2

total outcomes possible are 36
favourable outcomes are 35 (all the outcomes except 6,6 as it has a sum equal to 12)

so, probability is 35/36

hope it would help u :-)