Question

two dice are thrown simultaneously find the probability of getting

(A) A sum less than 5
(b) sum quather than 3
(c) Asam more than 3( d) product Inley than 12​

Answer 1

Answer:

Total outcome

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Total outcome = 36

Favourable outcomes

(2,6)(3,5)(3,6)(4,4)(4,5)(4,6)(5,3)

(5,4)(5,5,)(5,6)(6,2)(6,3)(6,4)(6,5)(6,6)

=15

Probability of getting a sum less than 5

$\frac{6}{36} = \frac{1}{6}$

probability of getting sum quarter more than 3

Favorable outcomes :-

(1,3) (1,4) (1,5) (1,6)

(2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Probability

$\frac{34}{36} = \frac{17}{18}$

Hope it helps you :)

You can find the other two by this method