Question

two dice are thrown simultaneously find the probability of getting an even number as the sum

Answer 1

Heya!!!

Here's your answer friend,

Here, Total outcomes :

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

=36 (total number of outcomes)

Total number of favourable outcomes = 18

Therefore, let E be the probability of getting an even number as the sun.

==> P(E) = Total number of favourable outcomes / Total number of outcomes

==> P(E) = 18/36
==>P(E) = 1/2

Hope it helps you : )

Answer 2

Hi
Ur answer is ....

No.of favourable outcomes/ no.of possible outcomes...

18/36 =1/2...

Hope it helpful...