Question

Two dice are thrown simultaneously. Find the probability of getting

i) a doublet of even numbers. ii) odd number on each die

iii) a sum less than 6.(very urgent please)...​

Answer 1

Answer:

i

total outcome = 36

favorable = 3 (i.e. 22, 44, 66)

p(E) = favorable outcome/total outcome

3/36

1/12

ii

total outcome= 36

favorable 27

(i.e. 1 with all 6, 3 with all 6, 5 with all 6, 2-1 ,2-3, 2-5 ,4-1, 4-3, 4-5, 6-1, ,6-3, 6-5)

p(E) = favorable outcome/total outcome

27/36

9/12

3/4

iii

total outcome= 36

favorable outcome = 10

i.e. 1-1_2-1_3-1_4-1_1-2_2-2_2-3_3-1_3-2_1-4

p(E) = favorable outcome/total outcome

10/36

5/18