two dice are thrown simultaneously.find the probability of getting
(1) Sum of numbers are 8
(2) sum of numbers at least 10
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Answer:
sorry I don't know of first but I can give you second
Step-by-step explanation:
Total number of possible cases =36
Favourable cases of getting a total of at least 10
={(4,6),(5,5),(5,6),(6,4),(6,5),(6,6)}
Total number of favourable cases =6
P(Total of at least 10) = 366=61
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