Question

two dice are thrown simultaneously. find the probability of getting a sum 8

Answer 1

favourable outcomes are(2,6), (3,5), (4,4), (5,3), (6,2)
total number of outcomes are 6^2=36
so the probability of getting 8=5/36

Answer 2

Answer:

Probability of getting a sum of 8 is $\frac{5}{36}$

Step-by-step explanation:

Given: Two Dice are thrown

To find: Probability of getting a sum of 8

Total no of outcome = 6² = 36

Sample Space is attached.

Let E be the event of getting a sum of 8

So, Favorable outcome = { (2,6) , (3,5) , (4,4) , (5,3) , (6,2) }

No. of favorable outcome = 5

$Probability=\frac{No.\,of\,favorable\,outcome}{Total\,no.\,of\,outcome}$

$P(E)=\frac{5}{36}$

Therefore, Probability of getting a sum of 8 is $\frac{5}{36}$