Question

Two dice are thrown simultaneously .find the probability that the sum of the two numbers appearing on the top is more than 8

Answer 1

Hope it is helpful..

Answer 2

Answer:

5/18

Step-by-step explanation:

Two dices are rolled .

Total Outcomes :

{1,1} ; {1,2} ; {1,3} ; {1,4} ; {1,5} ; {1,6}

{2,1} ; {2,2} ; {2,3} ; {2,4} ; {2,5} ; {2,6}

{3,1} ; {3,2} ; {3,3} ; {3,4} ; {3,5} ; {3,6}

{4,1} ; {4,2} ; {4,3} ; {4,4} ; {4,5} ; {4,6}

{5,1} ; {5,2} ; {5,3} ; {5,4} ; {5,5} ; {5,6}

{6,1} ; {6,2} ; {6,3} ; {6,4} ; {6,5} ; {6,6}

Total outcomes = 36

Now ,to find the probability that the sum of the two numbers appearing on the top is more than 8

Favorable outcomes =  {3,6}; {4,5} ; {4,6} ; {5,4} ; {5,5} ; {5,6}; {6,3} ; {6,4} ; {6,5} ; {6,6} = 10

So, probability that the sum of the two numbers appearing on the top is more than 8 = $\frac{10}{36} =\frac{5}{18}$

Hence the probability that the sum of the two numbers appearing on the top is more than 8 is 5/18.