Question

Two dice are thrown simultaneously. find the probability that the sum of the two numbers appearing on the top is less than or equal to10

Answer 1

$\frac{10}{11}$

Answer 2

probability of < 10 as sum = 33/36 = 11/12
bcoz total outcome is 36
and only three situation has sum greater than ten that is : 6,6 on the dices & 6 ,5 on the dices & 5,6 on the dices
so remaining outcomes will be 36 - 3 = 33
& probability is 11/12
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