Question

Two dice are thrown simultaneously. Find the probability that the sum of two numbers appearing on the top is more than 10

Answer 1

Probability =No. of favourable outcomes / Total no. of observations

Favourable Outcomes :- (6,6) (5,5) (6,4) (4,6) (5,6) (6,5)



Therefore Probability => 6/36 =>1/6

Answer 2

Answer:

Step-by-step explanation:

Maximum sum possible is 6+6=12

10 cases = 4+6,6+4,5+5

11 cases = 6+5,5+6

12 cases = 6+6

Total cases = 6×6=36

Favorable cases = 6

⇒ Probability = favorable outcomes/total outcomes   6/36 = 1/6

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