Question

two dice are thrown simultaneously find the probability that the number appearing product is equals to 7 12 and 6

Answer 1

U must make a sample piece before starting the problem to avoid mistakes. It goes like this.

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Product 7 => 0 because it's a prime number
Product 12 => (2,6)(3,4)(4,3)(6,2) = 4
Product 6 => (1,6)(2,3)(3,2)(6,1) = 4
Total Probability = 6x6 = 36

p(product 7) = 0/36 = 0
p(product 12) = 4/36 = 1/9
p(product 6) = 4/36 = 1/9.

Hope it helps.
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