Question

two dice are thrown simultaneously. find the probahility of getting a sum of numbers on faces shown up 8​.......plssssz answer it

Answer 1

Step-by-step explanation:

Two dices are thrown

Total possible outcomes=

(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)

(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)

(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)

(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)

(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)

(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

n(s)=36

n(A)=(2,6)(5,3)(4,4)(3,5)(6,2)

=5

probability=n(A)/n(S)

=5/36