Two dice are thrown simultaneously. Find the sum of the probaility of "getting a prime number as a sum" and probability of "getting a doublet of prime numbers".
Answers
Answer:
ANS =31/36
Step-by-step explanation:
if two dice are thrown together these are the possible outcomes
1,1 1,2 1,3 1,4 1,5 1,6
2,1 2,2 2,3 2,4 2,5 2,6
3,1 3,2 3,3 3,4 3,5 3,6
4,1 4,2 4,3 4,4 4,5 4,6
5,1 5,2 5,3 5,4 5,5 5,6
6,1 6,2 6,3 6,4 6,5 6,6
the probablility of getting a prime number as a sum = reqired observations / total observations
required observations 1,1 1,2 1,4 1,6 2,1 2,3 3,2 3,4 2,5 4,1 4,3 5,2 5,6 6,1 6,5
no of required observations = 15
thus probablity = 15/36
probability of doublet of prime numbers
required observations = 1,1 1,2 1,3 1,5 , 2,1 2,2 2,3 2,5 3,1 3,2 3,3 3,5 5,1 5,2 5,3 5,5
no of required observations = 16
thus probvabilty = 16 /36
acoording to the question we have to add both the probabailities
thus 15/36 + 16 /36 =31/36
ANS =31/36