Question

two dice are thrown simultaneously on e what is the probability of getting 8 as the sum of two numbers on its faces​

Answer 1

Answer:

total no.of outcome =36(6*6)

favorable outcome 6+2,5+3,4+4,,5+3,6+2

favorable number of outcome=5

required probability =favorable no.of outcomes/total no.of outcome=5/36

Answer 2

Answer:

For any outcome of first die there are 6 possible

outcomes for the second. Therefore there are6×6=36 possible outcomes .

Of all those outcomes ,the ones for which a+b=8

2+6,3+5,4+4,5+3,6+2or5 .

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