two dice are thrown simultaneously on e what is the probability of getting 8 as the sum of two numbers on its faces
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Answered by
3
Answer:
total no.of outcome =36(6*6)
favorable outcome 6+2,5+3,4+4,,5+3,6+2
favorable number of outcome=5
required probability =favorable no.of outcomes/total no.of outcome=5/36
Answered by
3
Answer:
For any outcome of first die there are 6 possible
outcomes for the second. Therefore there are6×6=36 possible outcomes .
Of all those outcomes ,the ones for which a+b=8
2+6,3+5,4+4,5+3,6+2or5 .
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