Question

two dice are thrown simultaneously. probability of getting a prime number on both dice is?​

Answer 1

Answer:

let the event be getting a prime number

no: of possible outcomes = 9

total no: of favourable outcomes = 36

P(E) = no: of possible outcomes/total no: of favourable outcomes

9/36

therefore the probability of getting a prime number = 9/36

(1,1) , (1,2) , (1,3) , (1,4) , (1,5) , (1,6)

(2,1) , (2,2) , (2,3) , (2,4) , (2,5) , (2,6)

(3,1) , (3,2) , (3,3) , (3,4) , (3,5) , (3,6)

(4,1) , (4,2) , (4,3) , (4,4) , (4,5) , (4,6)

(5,1) , (5,2) , (5,3) , (5,4) , (5,5) , (5,6)

(6,1) , (6,2) , (6,3) , (6,4) , (6,5) , (6,6)

I think this is the answer...............I hope it helps you

Answer 2

Answer:

Probability of getting prime number on both dice when two dice are thrown simultaneously is 1/4.

Explanation:

Explanation:Probability:

• Probability is the measure of occurrence of a random event..

Formula:

• Probability of an event = No. of favourable outcomes /Total no. of events.

Event:

• When two dice are thrown simultaneously Total no. of outcomes =36
• Here, No. of favourable outcomes = getting prime number on both the dice.
• When two dice are thrown simultaneously then the possibilities of getting prime numbers on both dice are given below

(2,2) (2,3) (3,2) (3,3) (2,5) (5,2) (5,5) (3,5) (5,3)

So,

No. of favourable outcomes = 9

Probability of an event = no. of favourable outcomes/ Total no. of outcomes

Hence, Probability of an event = 9/36 = 1/4

Know more about Probability:

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