Math, asked by piyrock345, 8 months ago

two dice are thrown simultaneously. probability of getting a prime number on both dice is?​

Answers

Answered by allekeerthi13
69

Answer:

let the event be getting a prime number

no: of possible outcomes = 9

total no: of favourable outcomes = 36

P(E) = no: of possible outcomes/total no: of favourable outcomes

9/36

therefore the probability of getting a prime number = 9/36

(1,1) , (1,2) , (1,3) , (1,4) , (1,5) , (1,6)

(2,1) , (2,2) , (2,3) , (2,4) , (2,5) , (2,6)

(3,1) , (3,2) , (3,3) , (3,4) , (3,5) , (3,6)

(4,1) , (4,2) , (4,3) , (4,4) , (4,5) , (4,6)

(5,1) , (5,2) , (5,3) , (5,4) , (5,5) , (5,6)

(6,1) , (6,2) , (6,3) , (6,4) , (6,5) , (6,6)

I think this is the answer...............I hope it helps you

Answered by parulsehgal06
4

Answer:

Probability of getting prime number on both dice when two dice are thrown simultaneously is 1/4.

Explanation:

Explanation:Probability:

  • Probability is the measure of occurrence of a random event..

Formula:

  • Probability of an event = No. of favourable outcomes /Total no. of events.

Event:

  • When two dice are thrown simultaneously Total no. of outcomes =36
  • Here, No. of favourable outcomes = getting prime number on both the dice.
  • When two dice are thrown simultaneously then the possibilities of getting prime numbers on both dice are given below

(2,2) (2,3) (3,2) (3,3) (2,5) (5,2) (5,5) (3,5) (5,3)

So,

No. of favourable outcomes = 9

Probability of an event = no. of favourable outcomes/ Total no. of outcomes

Hence, Probability of an event = 9/36 = 1/4

Know more about Probability:

https://brainly.com/question/15097725?referrer=searchResults

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