Question

*Two dice are thrown simultaneously. The probability of getting a sum of 9 is ………*

1️⃣ 1/10
2️⃣ 3/10
3️⃣ 1/9
4️⃣ 4/9​

Answer 1

☆ᴀɴsᴡᴇʀ:-

In two throws of a die,

n(S) = (6 x 6) = 36.

Let E = event of getting a sum

=(3, 6), (4, 5), (5, 4), (6, 3)

$P(E) = \frac{n(E)}{n(S)} = \frac{4}{36} = \frac{1}{9}$

sσ,thє σptíσn(c) ís thє cσrrєct αnswєr.

Answer 2

Given:

Two dice are thrown simultaneously.

To find:

Probability of getting a sum of 9.

Solution:

Following will be the total cases when two dice are thrown simultaneously:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) 3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

The cases which will result in  sum of 9 are:

(3,6), (4,5), (5,4), (6,3)

Therefore the probability of getting a sum of 9 will be:

= Number of cases which give a sum of 9/ total number of cases

= 4/ 36 = 1/9

Therefore the probability of getting a sum of 9 will be 1/9, hence option 3 is the correct one.